For Selenium this means that StaleElementException can occur. StaleElementException occurs if I find an element, the DOM gets updated then I try to interact with the element.
Actions like:
are not atomic. Just because it was all entered on one line, the code generated is no different than:driver.findElement(By.id("foo")).click();
If Javascript updates the page between the findElement call and the click call then I'll get a StaleElementException. It is not uncommon for this to occur on modern web pages. It will not happen consistently however. The timing has to be just right for this bug to occur.By fooID = By.id("foo"); WebElement foo = driver.findElement(fooID); foo.click();
Generally speaking, if you know the page has Javascript which automatically updates the DOM, you should assume a StaleElementException will occur. It might not occur when you are writing the test or running it on your local machine but it will happen. Often it will happen after you have 5000 test cases and haven't touched this code for over a year. Like most developers, if it worked yesterday and stopped working today you'll look at what you changed recently and never find this bug.
So how do I handle it? I use the following click method:
This will attempt to find and click the element. If the DOM changes between the find and click, it will try again. The idea is that if it failed and I try again immediately the second attempt will succeed. If the DOM changes are very rapid then this will not work. At that point you need to get development to slow down the DOM change so this works or you need to make a custom solution for that particular project.public boolean retryingFindClick(By by) { boolean result = false; int attempts = 0; while(attempts < 2) { try { driver.findElement(by).click(); result = true; break; } catch(StaleElementException e) { } attempts++; } return result; }
The method takes as input a locator for the element you want to click. If it is successful it will return true. Otherwise it returns false. If it makes it past the click call, it will return true. All other failures will return false.
Personally, I would argue this should always work. If the developers are refreshing the page too quickly then it will be overloading the browser on the client machine.
4 comments:
Thank you Darrell a lot for this hint.
I've spent for about 3 weeks trying to understand what do I do wrong when I ocasionally get StaleElementReferenceException.
Now I see thet there is just a specific of whandling of dynamic pages.
Good luck!
great solution...
I've been trying to get a solution to this problem since almost a month & none worked except yours...
Thanks do much.
public static String getValue(final WebDriver driver, final By locator)
{
Wait wait = new FluentWait(driver)
.withTimeout(30, TimeUnit.SECONDS)
.pollingEvery(1, TimeUnit.SECONDS)
.ignoring(StaleElementReferenceException.class);
String value = wait.until(new Function() {
public String apply(WebDriver driver) {
return driver.findElement(locator).getAttribute("value");
}
});
return value;
}
Is working for me
Hey Darrell, Thanks a lot.. You saved my job... :-)
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